Answer with Explanation-Aptitude Question For SSC Bank -Time and Distance(13 Dec)
2019-12-24 15:49:54
- Pinnacle Admin
Answers :
1). Answer: d)
Explanation:
Total work = men*days
Total units of work = 25*16 = 400 units
Work done in 4 days = 25*4 = 100 units
Remaining work = 400 – 100 = 300 units
Let the number of men left after 4 days be x,
According to the question,
300/15 = 25 – x
20 = 25 – x
X = 5 men
After 4 days from the start of the work, 5 men left the job.
2). Answer: a)
Explanation:
Total work = (men (or) women)*days
Work equal,
(10w + 6m)*5 = (7w + 8m)*6
50w + 30m = 42w + 48m
8w = 18m
4w = 9m = > 1w = (9/4) m
10w + 6m = 10*(9/4) m + 6m = (57/2) m
12w + 5m = 12*(9/4) m + 3 m = 30 m
Women days
(57/2) 5
30 ?
(57/2)*5 = 30x
X = (57/2)*(5/30) = 4 9/12 = 4 ¾ days
3). Answer: c)
Explanation:
Total work = men * days
Total work = 20*12 = 240
6 days work = 20*6 = 120
Remaining work = 240 – 120 = 120 work
Now, the total men = 20 – 5 = 15 men
Remaining work can be completed in,
= > 120/15 = 8 days
Remaining work gets completed in 8 days.
4). Answer: b)
Explanation:
1/12 + 1/16 + 1/C = 3/16
1/C = (3/16) – (1/12 + 1/16)
(1/C) = (3/16) – (7/48) = 1/24
C can do it in 24 days.
Efficiency of A, B and C = (1/12) : (1/16) : (1/24) = 4 : 3 : 2
9’s = 4500
1’s = 500
The share of C = Rs. 1000
5). Answer: d)
Explanation:
Shortcut:
Men women days
4 7 49
6 14 ?
Required days = (4*7*49)/(56 + 42) = (4*7*49)/98
= > 14 days
(Or)
4 men = 7 women
1 men = (7/4) women
6 m + 14 w = 6*(7/4) w + 14 w = 49/2 w
Women days
7 49
49/2 ?
= > (7*49*2)/49 = 14 days
6). Answer: d)
Explanation:
Manohar and Ragu’s one day work = (1/15) + (1/18) = 11/90
Manohar and Ragu’s 6 day work = (11/90)*6 = 11/15
Remaining work 4/15 done by Manohar and Ranjith
Manohar and Ranjith finished it in 1 1/3 days
(4/15)*(Manohar + Ranjith)’s whole work = (4/3)
(Manohar + Ranjith)’s whole work = (4/3)*(15/4) = 5 days
Ranjith’s one day work = (1/5) – (1/15) = 2/15
Ranjith alone can complete the work in 7 ½ days
7). Answer: c)
Explanation:
A, B and C together complete the work in = 4 32/37 days = 180/37 days
(A + B + C)’s one day work = 37/180
B’s one day work = 1/18
C’s one day work = 1/15
A’s one day work = (37/180) – (1/18 + 1/15)
= > 37/180 – 11/90 = 15/180 = 1/12
A can take to complete the work alone in 12 days
8). Answer: c)
Explanation:
A can complete 3/5th of the work = 6 days
A can complete the whole work in = 6*(5/3) = 10 days
B can complete 2/7th of the work = 4 days
B can complete the whole work in = 4*(7/2) = 14 days
(A + B)’s one day work = (1/10) + (1/14) = 24/(10*14) = 6/35
A and B together can complete the work in, 35/6 = 5 5/6 days
9). Answer: b)
Explanation:
Efficiency ratio = > Q : P = 140 : 100 = 7 : 5
Days ratio = > Q : P = 5 : 7
P can do a piece of work in 21 days
7’s = 21 = > 1’s = 3
So Q can complete the work in 15 days
= > 1/21 + 1/15
= > 36/(21*15) = 4/35
P and Q together can complete the work in 35/4 = 8 ¾ days
10). Answer: b)
Explanation:
(x + 3) person can do the work in = (x – 5)
(x – 3)*x = (x + 3) (x – 5)
X2 – 3x = x2 – 5x + 3x – 15
X = 15
Person days
12 15
20 ?
(12*15) = 20*y
Y = 180/20 = 9 days
